Java Varargs - Simple Addition Hackerrank Solution For Explanation Watch Video: Sample Input 1 2 3 4 5 6 Sample Output 1+2=3 1+2+3=6 1+2+3+4+5=15 1+2+3+4+5+6=21 Code: import java.io.*; import java.lang.reflect.*; import java.util.*; import java.text.*; import java.math.*; import java.util.regex.*; class Add{ public static void add(int... arr){ int sum = 0; for(int i=0;i<arr.length-1;i++){ System.out.print(arr[i]+"+"); sum += arr[i]; } sum += arr[arr.length-1]; System.out.print(arr[arr.length-1]+"="); System.out.println(sum); } } public class Solution { public static void main(String[] args) { try { BufferedReader br= new BufferedReader( new InputStreamReader(System.in)); int n1=Integer.parseInt(br.readLine()); int n2=Integer.parseInt(br.readLine()); int n3=Integer.parseInt(br.readLine());