Java Exception Handling (Try-catch) Hackerrank Solution For Explanation Watch Video: Sample Input 0: 10 3 Sample Output 0: 3 Sample Input 1: 10 Hello Sample Output 1: java.util.InputMismatchException Sample Input 2: 10 0 Sample Output 2: java.lang.ArithmeticException: / by zero Sample Input 3: 23.323 0 Sample Output 3: java.util.InputMismatchException Code: import java.io.*; import java.util.*; import java.text.*; import java.math.*; import java.util.regex.*; public class Solution { public static void main(String[] args) { try { Scanner scn = new Scanner(System.in); int x = scn.nextInt(); int y = scn.nextInt(); System.out.println(x/y); } catch (InputMismatchException e){ System.out.println(e.getClass().getName()); } catch (ArithmeticException e){ System.out.println(e); } } }