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Day 20: Sorting Hackerrank Solution Java

 Day 20: Sorting Hackerrank Solution Java

For Explanation Watch Video:


Sample Input 0

3
1 2 3

Sample Output 0

Array is sorted in 0 swaps.
First Element: 1
Last Element: 3
Code:
import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int n = in.nextInt();
        int[] a = new int[n];
        for(int a_i=0; a_i < n; a_i++){
            a[a_i] = in.nextInt();
        }
        int numberOfSwaps = 0;
        for (int i = 0; i < n; i++) {
    
            for (int j = 0; j < n - 1; j++) {
                // Swap adjacent elements if they are in decreasing order
                if (a[j] > a[j + 1]) {
                    int temp = a[j];
                    a[j] = a[j+1];
                    a[j+1] = temp;
                    numberOfSwaps++;
            }
        }
    
        // If no elements were swapped during a traversal, array is sorted
        if (numberOfSwaps == 0) {
            break;
        }
    }
     System.out.println("Array is sorted in "+numberOfSwaps+" swaps.");
     System.out.println("First Element: "+a[0]);
     System.out.println("Last Element: "+a[n-1]);
    }
}

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