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Java Regex Hackerrank Solution

 Java Regex Hackerrank Solution

For Explanation Watch Video:


Sample Input

000.12.12.034
121.234.12.12
23.45.12.56
00.12.123.123123.123
122.23
Hello.IP

Sample Output

true
true
true
false
false
false
Code:
import java.util.regex.Matcher;
import java.util.regex.Pattern;
import java.util.Scanner;

class Solution{

    public static void main(String[] args){
        Scanner in = new Scanner(System.in);
        while(in.hasNext()){
            String IP = in.next();
            System.out.println(IP.matches(new MyRegex().pattern));
        }

    }
}

//Write your code here
class MyRegex{
    //1--> it can contain single digit i.e ([0-9]);

    //2--> It can contain two digits i.e ([0-9][0-9]);

    //3--> Range is (099 to 199)i.e((0|1)[0-9][0-9]);       

    //4--> range is (200 - 249) i.e (2[0-4][0-9]) ;

    //5--> range is (250-255) i.e (25[0-5]);    
    String reg = "([0-9]|[0-9][0-9]|(0|1)[0-9][0-9]|2[0-4][0-9]|25[0-5])";
    public String pattern = reg+"."+reg+"."+reg+"."+reg;
}

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