Java Exception Handling (Try-catch) Hackerrank Solution

 Java Exception Handling (Try-catch) Hackerrank Solution

For Explanation Watch Video:

Sample Input 0:

10
3

Sample Output 0:

3

Sample Input 1:

10
Hello

Sample Output 1:

java.util.InputMismatchException

Sample Input 2:

10
0

Sample Output 2:

java.lang.ArithmeticException: / by zero

Sample Input 3:

23.323
0

Sample Output 3:

java.util.InputMismatchException

Code:

import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;
public class Solution {
    public static void main(String[] args) {
        try{
            Scanner scn = new Scanner(System.in);
            int x = scn.nextInt();
            int y = scn.nextInt();
            System.out.println(x/y);
        }catch(InputMismatchException e){
            System.out.println(e.getClass().getName());
        }catch(ArithmeticException e){
            System.out.println(e);
        }
    }
}