Java Exception Handling Hackerrank solution

 Java Exception Handling Hackerrank solution

For Explanation Watch Video:

Sample Input 0

3 5
2 4
0 0
-1 -2
-1 3

Sample Output 0

243
16
java.lang.Exception: n and p should not be zero.
java.lang.Exception: n or p should not be negative.
java.lang.Exception: n or p should not be negative.

Code:

import java.util.Scanner;
class MyCalculator {
    /*
    * Create the method long power(int, int) here.
    */
    public long power(int n,int p)throws Exception{
        if(n<0 || p<0){
            throw new Exception("n or p should not be negative.");
        }else if(n==0 && p==0){
            throw new Exception("n and p should not be zero.");
        }else{
            return (long)Math.pow(n,p);
        }
        
    }
}
public class Solution {
    public static final MyCalculator my_calculator = new MyCalculator();
    public static final Scanner in = new Scanner(System.in);
    
    public static void main(String[] args) {
        while (in .hasNextInt()) {
            int n = in .nextInt();
            int p = in .nextInt();
            
            try {
                System.out.println(my_calculator.power(n, p));
            } catch (Exception e) {
                System.out.println(e);
            }
        }
    }
}